IPL Mega Auction date announced, players will be auctioned for 2 days in this city
Indian Premier League 2025 mega auction dates announced
The IPL Governing Council has officially announced the dates for the mega auction to be held before the 18th season of the Indian Premier League i.e. IPL to be played in the year 2025, in which this time the players auction will be held on 24 and 25 November in Saudi Arabia. Will be in Jeddah city. On October 31, all the 10 IPL franchises had announced the names of their retained players, after which many big names will be part of the auction this time. In this, a total of 204 players including all the teams are vacant.
A total of 46 players have been retained and the remaining players will be part of the auction.
The upcoming mega auction of IPL is expected to be very exciting, in which many big players like Rishabh Pant and Shreyas Iyer will be a part of it, hence it is certain that big bids will be made for them. This time all the 10 franchises together have retained a total of 46 players, whose names were announced on October 31. During the two days in which the IPL Mega Auction is being organised, the Indian team will be playing a Test match in Perth on the tour of Australia and this auction will take place when the third and fourth day’s play is being played. Earlier in the year 2024, IPL mini auction was held in Dubai.
Team will be formed for the next three years
Mega auction is organized every three years in IPL, in which many major changes are seen in all the teams. This time, after the mega auction is organized, the mega auction will be organized after the IPL season to be played in the year 2027. This time, all the teams had got a purse of Rs 120 crore before the auction, in which after the retained players, everyone’s money has definitely reduced, in which the team of Punjab Kings will come with the highest purse at the time of auction, who currently have Rs 110.5 crore. It is crores of rupees.
read this also
IND vs SA: How to watch the match live on TV and mobile, this is the easiest way
